# Help?

1.    1. Given the exemplification facts.

 x: 26 16 19 24 15

(a) Confront the class.
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(b) Verify that
Σx = 100 and Σx2 = 2094.

 Σx [removed] Σx2 [removed]

(c) Use the results of sbelow (b) and expend reckoning formulas to estimate the exemplification variance s2 and exemplification type flexion s. (Enter your replys to one decimal assign.)

 s2 [removed] s [removed]

(d) Use the defining formulas to estimate the exemplification variance s2 and exemplification type flexion s. (Enter your replys to one decimal assign.)

 s2 [removed] s [removed]

(e) Suppose the attached facts hint the all population of all x values. Estimate the population variance
σ2 and population type flexion σ. (Enter your replys to one decimal assign.)

 σ2 [removed] σ [removed]

2. Police vmanifestation opportunity to an pitch overcome is the variety among the opportunity the overcome is leading common by the dispatcher and the opportunity a watchman car radios that it has arrived at the show. Over a hanker date of opportunity, it has been fixed that the police vmanifestation opportunity has a ordinary division behind a while a moderation of 8.9 minutes and a type flexion of 1.5 minutes. For a unpremeditatedly common pitch overcome, confront the forthcoming probabilities. (Round your replys to impure decimal assigns.)

(a) the vmanifestation opportunity is among 5 and 10 minutes
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(b) the vmanifestation opportunity is less than 5 minutes
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(c) the vmanifestation opportunity is further than 10 minutes
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3. Let x be a unpremeditated wavering that represents the equalize of glucose in the dignity (milligrams per deciliter of dignity) behind a 12 hour unyielding. Assume that for crowd below 50 years old, x has a division that is closely ordinary, behind a while moderation μ = 69 and estimated type flexion σ = 26. A cupel result x < 40 is an manifestation of exact surplus insulin, and medication is usually prescribed.

(a) What is the presumption that, on a unique cupel, x < 40? (Round your reply to impure decimal assigns.)
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(b) Suppose a schoolman uses the average x for two cupels charmed about a week separate. What can we say about the presumption division of xHint: See Theorem 6.1.

[removed]The presumption division of x is closely ordinary behind a while μx = 69 and σx = 18.38.[removed]The presumption division of x is closely ordinary behind a while μx = 69 and σx = 13.00.    [removed]The presumption division of x is closely ordinary behind a while μx = 69 and σx = 26.[removed]The presumption division of x is not ordinary.

What is the presumption that x < 40? (Round your reply to impure decimal assigns.)
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(c) Repeat sbelow (b) for n = 3 cupels charmed a week separate. (Round your reply to impure decimal assigns.)
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(d) Repeat sbelow (b) for n = 5 cupels charmed a week separate. (Round your reply to impure decimal assigns.)
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(e) Compare your replys to sunders (a), (b), (c), and (d). Did the probabilities retrench as n increased?

[removed]Yes[removed]No

Explain what this potentiality hint if you were a schoolman or a comfort.

[removed]The further cupels a enduring completes, the stronger is the indication for surplus insulin.[removed]The further cupels a enduring completes, the stronger is the indication for noncommunication of insulin.    [removed]The further cupels a enduring completes, the weaker is the indication for noncommunication of insulin.[removed]The further cupels a enduring completes, the weaker is the indication for surplus insulin.